Is cot^2(θ)-cot^2(θ)=cos^2(θ)cot^2(θ) ?

The answer to whether cot^2(θ)-cot^2(θ)=cos^2(θ)cot^2(θ) is False

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prove cot^2(θ)-cot^2(θ)=cos^2(θ)cot^2(θ)

prove

cot^{2} (θ) - cot^{2} (θ) = cos^{2} (θ) cot^{2} (θ)

False

Solution steps

cot^{2} (θ) - cot^{2} (θ) = cos^{2} (θ) cot^{2} (θ)

Show that the two sides are not equal

\Rightarrow False

tan (2 π - θ) = - tan (θ)

sin^{4} (θ) - cos^{4} (θ) = 1 - 2 cos^{2} (θ)

\frac{1 + tan ( x )}{1 - tan ( x )} + \frac{1 + cot ( x )}{1 - cot ( x )} = 0

2 - sec^{2} (x) = 1 - tan^{2} (x)

tan (x) (1 - sin^{2} (x)) = \frac{1}{2} sin (2 x)

Is cot^2(θ)-cot^2(θ)=cos^2(θ)cot^2(θ) ?
The answer to whether cot^2(θ)-cot^2(θ)=cos^2(θ)cot^2(θ) is False