Is sin^2(x)+cos^2(x)=sin(x)csc(x) ?

The answer to whether sin^2(x)+cos^2(x)=sin(x)csc(x) is True

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prove sin^2(x)+cos^2(x)=sin(x)csc(x)

prove

sin^{2} (x) + cos^{2} (x) = sin (x) csc (x)

True

Solution steps

sin^{2} (x) + cos^{2} (x) = sin (x) csc (x)

Manipulating right side

sin (x) csc (x)

Express with sin, cos

= 1

Rewrite using trig identities

= cos^{2} (x) + sin^{2} (x)

= sin^{2} (x) + cos^{2} (x)

We showed that the two sides could take the same form

\Rightarrow True

(1 - sin^{2} (θ)) (1 + tan^{2} (θ)) = 1

sin (x) + cos (x) \cdot cot (x) = csc (x)

cos (4 x) = 1 - 8 sin^{2} (x) cos^{2} (x)

\frac{sin ( x )}{1 - cos ( - x )} = csc (x) + cot (x)

tan (x) - tan (y) = \frac{sin ( x - y )}{cos ( x ) cos ( y )}

Is sin^2(x)+cos^2(x)=sin(x)csc(x) ?
The answer to whether sin^2(x)+cos^2(x)=sin(x)csc(x) is True