Is (sin(y)+tan(y))/(1+sec(y))=sin(y) ?

The answer to whether (sin(y)+tan(y))/(1+sec(y))=sin(y) is True

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prove (sin(y)+tan(y))/(1+sec(y))=sin(y)

prove

\frac{sin ( y ) + tan ( y )}{1 + sec ( y )} = sin (y)

True

Solution steps

\frac{sin ( y ) + tan ( y )}{1 + sec ( y )} = sin (y)

Manipulating left side

\frac{sin ( y ) + tan ( y )}{1 + sec ( y )}

Express with sin, cos

= sin (y)

We showed that the two sides could take the same form

\Rightarrow True

cos^{2} (2 x) - sin^{2} (2 x) = cos (4 x)

\frac{sec ^{2} ( x ) - 1}{sin ( x )} = \frac{sin ( x )}{1 - sin ^{2} ( x )}

sin (\frac{π}{4} + x) + sin (\frac{π}{4} - x) = 2 cos (x)

sin (x) cot (x) sec (x) = 1

cot^{2} (a) + 1 = \frac{1}{sin ^{2} ( a )}

Is (sin(y)+tan(y))/(1+sec(y))=sin(y) ?
The answer to whether (sin(y)+tan(y))/(1+sec(y))=sin(y) is True