Is (sin^2(θ))/(cos(θ))=sec(θ)-cos(θ) ?

The answer to whether (sin^2(θ))/(cos(θ))=sec(θ)-cos(θ) is True

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prove (sin^2(θ))/(cos(θ))=sec(θ)-cos(θ)

prove

\frac{sin ^{2} ( θ )}{cos ( θ )} = sec (θ) - cos (θ)

True

Solution steps

\frac{sin ^{2} ( θ )}{cos ( θ )} = sec (θ) - cos (θ)

Manipulating right side

sec (θ) - cos (θ)

Express with sin, cos

= \frac{1 - cos ^{2} ( θ )}{cos ( θ )}

Rewrite using trig identities

= \frac{sin ^{2} ( θ )}{cos ( θ )}

We showed that the two sides could take the same form

\Rightarrow True

\frac{csc ( x )}{sin ( x )} - \frac{cot ( x )}{tan ( x )} = 1

\frac{sin ( x )}{1 + cos ( x )} = csc (x) - cot (x)

(1 - cos^{2} (x)) cot (x) = sin (x) cos (x)

sin (x) tan (x) = sec (x) - cos (x)

tan^{2} (x) - sin^{2} (x) = sin^{4} (x) sec^{2} (x)

Is (sin^2(θ))/(cos(θ))=sec(θ)-cos(θ) ?
The answer to whether (sin^2(θ))/(cos(θ))=sec(θ)-cos(θ) is True