Is tan^2(θ)sin^2(θ)=tan^2(θ)-sin^2(θ) ?

The answer to whether tan^2(θ)sin^2(θ)=tan^2(θ)-sin^2(θ) is True

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prove tan^2(θ)sin^2(θ)=tan^2(θ)-sin^2(θ)

prove

tan^{2} (θ) sin^{2} (θ) = tan^{2} (θ) - sin^{2} (θ)

True

Solution steps

tan^{2} (θ) sin^{2} (θ) = tan^{2} (θ) - sin^{2} (θ)

Manipulating left side

tan^{2} (θ) sin^{2} (θ)

Rewrite using trig identities

= tan^{2} (θ) (1 - cos^{2} (θ))

Expand

(1 - cos^{2} (θ)) tan^{2} (θ) : tan^{2} (θ) - tan^{2} (θ) cos^{2} (θ)

= tan^{2} (θ) - cos^{2} (θ) tan^{2} (θ)

Rewrite using trig identities

= tan^{2} (θ) - sin^{2} (θ)

We showed that the two sides could take the same form

\Rightarrow True

cos (x) (sec (x) - cos (x)) = sin^{2} (x)

cos (z + w) = cos (z) cos (w) - sin (z) sin (w)

(1 - cos^{2} (θ)) csc^{2} (θ) = 1

tan (π - θ) = - tan (θ)

(cot (θ) + tan (θ)) cos (θ) = csc (θ)

Is tan^2(θ)sin^2(θ)=tan^2(θ)-sin^2(θ) ?
The answer to whether tan^2(θ)sin^2(θ)=tan^2(θ)-sin^2(θ) is True