Is sec(x)-tan(x)=(1-sin(x))/(cos(x)) ?

The answer to whether sec(x)-tan(x)=(1-sin(x))/(cos(x)) is True

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prove sec(x)-tan(x)=(1-sin(x))/(cos(x))

prove

sec (x) - tan (x) = \frac{1 - sin ( x )}{cos ( x )}

True

Solution steps

sec (x) - tan (x) = \frac{1 - sin ( x )}{cos ( x )}

Manipulating left side

sec (x) - tan (x)

Express with sin, cos

= \frac{1 - sin ( x )}{cos ( x )}

We showed that the two sides could take the same form

\Rightarrow True

sin (\frac{3 π}{2} + x) = - cos (x)

\frac{cos ^{2} ( t )}{sin ( t )} = csc (t) - sin (t)

sin (x) tan (x) = \frac{1 - cos ^{2} ( x )}{cos ( x )}

sec (u) + tan (u) = \frac{cos ( u )}{1 - sin ( u )}

cos (x - \frac{π}{6}) - cos (x + \frac{π}{6}) = sin (x)

Is sec(x)-tan(x)=(1-sin(x))/(cos(x)) ?
The answer to whether sec(x)-tan(x)=(1-sin(x))/(cos(x)) is True