Is cos^2(β)-sin^2(β)=1-2sin^2(β) ?

The answer to whether cos^2(β)-sin^2(β)=1-2sin^2(β) is True

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove cos^2(β)-sin^2(β)=1-2sin^2(β)

prove

cos^{2} (β) - sin^{2} (β) = 1 - 2 sin^{2} (β)

True

Solution steps

cos^{2} (β) - sin^{2} (β) = 1 - 2 sin^{2} (β)

Manipulating left side

cos^{2} (β) - sin^{2} (β)

Rewrite using trig identities

= 1 - 2 sin^{2} (β)

We showed that the two sides could take the same form

\Rightarrow True

csc (2 x) = \frac{1}{2} sec (x) csc (x)

\frac{1}{1 - tan ^{2} ( x )} + \frac{1}{1 - cot ^{2} ( x )} = 1

tan (2 a) = \frac{2 tan ( a )}{1 - tan ^{2} ( a )}

csc (x) - cot (x) = \frac{1}{csc ( x ) + cot ( x )}

cos (π - θ) + sin (\frac{π}{2} + θ) = 0

Is cos^2(β)-sin^2(β)=1-2sin^2(β) ?
The answer to whether cos^2(β)-sin^2(β)=1-2sin^2(β) is True