Is (csc(θ))/(sec(θ))=cot(θ) ?

The answer to whether (csc(θ))/(sec(θ))=cot(θ) is True

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prove (csc(θ))/(sec(θ))=cot(θ)

prove

\frac{csc ( θ )}{sec ( θ )} = cot (θ)

True

Solution steps

\frac{csc ( θ )}{sec ( θ )} = cot (θ)

Manipulating left side

\frac{csc ( θ )}{sec ( θ )}

Express with sin, cos

= \frac{cos ( θ )}{sin ( θ )}

Use the basic trigonometric identity:

\frac{cos ( x )}{sin ( x )} = cot (x)

= cot (θ)

We showed that the two sides could take the same form

\Rightarrow True

sec (x) csc (x) = tan (x) + cot (x)

sin (x) \cdot sec (x) = tan (x)

cot (B) sin (B) = cos (B)

\frac{cos ( x )}{sec ( x ) - tan ( x )} = 1 + sin (x)

\frac{csc ^{2} ( x )}{sec ^{2} ( x )} = csc^{2} (x) - 1

Is (csc(θ))/(sec(θ))=cot(θ) ?
The answer to whether (csc(θ))/(sec(θ))=cot(θ) is True