Is cos((3pi)/2-θ)=-sin(θ) ?

The answer to whether cos((3pi)/2-θ)=-sin(θ) is True

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prove cos((3pi)/2-θ)=-sin(θ)

prove

cos (\frac{3 π}{2} - θ) = - sin (θ)

True

Solution steps

cos (\frac{3 π}{2} - θ) = - sin (θ)

Manipulating left side

cos (\frac{3 π}{2} - θ)

Rewrite using trig identities

= - sin (θ)

We showed that the two sides could take the same form

\Rightarrow True

1 + tan^{2} (x) = \frac{1}{cos ^{2} ( x )}

cos (B) csc (B) tan (B) = 1

\frac{tan ( θ ) + cot ( θ )}{tan ( θ )} = csc^{2} (θ)

sin (6 0^{\circ}) = 2 sin (3 0^{\circ}) cos (3 0^{\circ})

\frac{cos ( θ )}{1 + sin ( θ )} + tan (θ) = sec (θ)

Is cos((3pi)/2-θ)=-sin(θ) ?
The answer to whether cos((3pi)/2-θ)=-sin(θ) is True