Is (sin(θ)+tan(θ))/(1+sec(θ))=sin(θ) ?

The answer to whether (sin(θ)+tan(θ))/(1+sec(θ))=sin(θ) is True

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prove (sin(θ)+tan(θ))/(1+sec(θ))=sin(θ)

prove

\frac{sin ( θ ) + tan ( θ )}{1 + sec ( θ )} = sin (θ)

True

Solution steps

\frac{sin ( θ ) + tan ( θ )}{1 + sec ( θ )} = sin (θ)

Manipulating left side

\frac{sin ( θ ) + tan ( θ )}{1 + sec ( θ )}

Express with sin, cos

= sin (θ)

We showed that the two sides could take the same form

\Rightarrow True

sec (2 θ) = \frac{sec ^{2} ( θ )}{1 - tan ^{2} ( θ )}

cos (2 a) = cos^{2} (a) - sin^{2} (a)

tan (θ) + cot (θ) = sec (θ) \cdot csc (θ)

\frac{cos ( x )}{csc ( x ) + 1} + \frac{cos ( x )}{csc ( x ) - 1} = 2 tan (x)

\frac{cos ( x ) csc ( x )}{cot ^{2} ( x )} = tan (x)

Is (sin(θ)+tan(θ))/(1+sec(θ))=sin(θ) ?
The answer to whether (sin(θ)+tan(θ))/(1+sec(θ))=sin(θ) is True