Is 1-cos^2(θ)=sin(θ)cos(θ)tan(θ) ?

The answer to whether 1-cos^2(θ)=sin(θ)cos(θ)tan(θ) is True

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prove 1-cos^2(θ)=sin(θ)cos(θ)tan(θ)

prove

1 - cos^{2} (θ) = sin (θ) cos (θ) tan (θ)

True

Solution steps

1 - cos^{2} (θ) = sin (θ) cos (θ) tan (θ)

Manipulating right side

sin (θ) cos (θ) tan (θ)

Express with sin, cos

= sin^{2} (θ)

Rewrite using trig identities

= 1 - cos^{2} (θ)

We showed that the two sides could take the same form

\Rightarrow True

arctan (x) = \frac{1}{tan ( x )}

tan (\frac{θ}{2}) = csc (θ) - cot (θ)

cos (4 x) = 1 - 8 sin^{2} (x) + 8 sin^{4} (x)

(sin (θ) - cos (θ))^{2} = 1 - sin (2 θ)

\frac{sec ( x )}{csc ( x )} = tan (x)

Is 1-cos^2(θ)=sin(θ)cos(θ)tan(θ) ?
The answer to whether 1-cos^2(θ)=sin(θ)cos(θ)tan(θ) is True