Is sin^2(x)+sin^2(x)cot^2(x)=1 ?

The answer to whether sin^2(x)+sin^2(x)cot^2(x)=1 is True

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove sin^2(x)+sin^2(x)cot^2(x)=1

prove

sin^{2} (x) + sin^{2} (x) cot^{2} (x) = 1

True

Solution steps

sin^{2} (x) + sin^{2} (x) cot^{2} (x) = 1

Manipulating left side

sin^{2} (x) + sin^{2} (x) cot^{2} (x)

Express with sin, cos

= cos^{2} (x) + sin^{2} (x)

Rewrite using trig identities

= 1

We showed that the two sides could take the same form

\Rightarrow True

tan (x) = \frac{1}{cot ( x )}

sin^{2} (\frac{θ}{2}) = \frac{sec ( θ ) - 1}{2 sec ( θ )}

cot (t) csc (t) = \frac{csc ^{2} ( t ) - 1}{cos ( t )}

\frac{1}{1 + sin ( t )} = (sec (t) - tan (t)) sec (t)

\frac{1 - cos ( x )}{1 + cos ( x )} = tan^{2} (\frac{x}{2})

Is sin^2(x)+sin^2(x)cot^2(x)=1 ?
The answer to whether sin^2(x)+sin^2(x)cot^2(x)=1 is True