Is sin^2(x)cot^2(x)+sin^2(x)=1 ?

The answer to whether sin^2(x)cot^2(x)+sin^2(x)=1 is True

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prove sin^2(x)cot^2(x)+sin^2(x)=1

prove

sin^{2} (x) cot^{2} (x) + sin^{2} (x) = 1

True

Solution steps

sin^{2} (x) cot^{2} (x) + sin^{2} (x) = 1

Manipulating left side

sin^{2} (x) cot^{2} (x) + sin^{2} (x)

Express with sin, cos

= cos^{2} (x) + sin^{2} (x)

Rewrite using trig identities

= 1

We showed that the two sides could take the same form

\Rightarrow True

- tan (θ) cos (θ) = sin (- θ)

(sin (x) + cos (x))^{2} = 2 sin (x) cos (x) + 1

sin^{2} (2 x) = \frac{1}{2} (1 - cos (4 x))

sec (t) - \frac{cos ( t )}{1 + sin ( t )} = tan (t)

sec (x) - cos (x) = sin (x) \cdot tan (x)

Is sin^2(x)cot^2(x)+sin^2(x)=1 ?
The answer to whether sin^2(x)cot^2(x)+sin^2(x)=1 is True