Is tan^2(x)sec^2(x)+sec^2(x)=sec^4(x) ?

The answer to whether tan^2(x)sec^2(x)+sec^2(x)=sec^4(x) is True

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove tan^2(x)sec^2(x)+sec^2(x)=sec^4(x)

prove

tan^{2} (x) sec^{2} (x) + sec^{2} (x) = sec^{4} (x)

True

Solution steps

tan^{2} (x) sec^{2} (x) + sec^{2} (x) = sec^{4} (x)

Manipulating left side

tan^{2} (x) sec^{2} (x) + sec^{2} (x)

Rewrite using trig identities

= sec^{4} (x)

We showed that the two sides could take the same form

\Rightarrow True

1 - sin (x) = \frac{cos ^{2} ( x )}{1 + sin ( x )}

sec (θ) tan (θ) = sin (θ) sec^{2} (θ)

(sec (u) - tan (u)) (csc (u) + 1) = cot (u)

cot (2 θ) = \frac{csc ^{2} ( θ ) - 2}{2 cot ( θ )}

tan (θ + \frac{π}{4}) = \frac{1 + tan ( θ )}{1 - tan ( θ )}

Is tan^2(x)sec^2(x)+sec^2(x)=sec^4(x) ?
The answer to whether tan^2(x)sec^2(x)+sec^2(x)=sec^4(x) is True