Is sin(θ)+cos(θ)=(1+tan(θ))/(sec(θ)) ?

The answer to whether sin(θ)+cos(θ)=(1+tan(θ))/(sec(θ)) is True

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prove sin(θ)+cos(θ)=(1+tan(θ))/(sec(θ))

prove

sin (θ) + cos (θ) = \frac{1 + tan ( θ )}{sec ( θ )}

True

Solution steps

sin (θ) + cos (θ) = \frac{1 + tan ( θ )}{sec ( θ )}

Manipulating right side

\frac{1 + tan ( θ )}{sec ( θ )}

Express with sin, cos

= cos (θ) + sin (θ)

= sin (θ) + cos (θ)

We showed that the two sides could take the same form

\Rightarrow True

tan^{4} (x) - sec^{4} (x) = - 2 tan^{2} (x) - 1

\frac{1}{1 + cos ( x )} = csc^{2} (x) - csc (x) cot (x)

sin^{2} (2 x) = 1 - cos^{2} (2 x)

sin (\frac{A}{2}) = \frac{1}{2} sin (A)

\frac{cos ( θ )}{1 - sin ( θ )} = tan (θ) + sec (θ)

Is sin(θ)+cos(θ)=(1+tan(θ))/(sec(θ)) ?
The answer to whether sin(θ)+cos(θ)=(1+tan(θ))/(sec(θ)) is True