Is 2sin^2(θ)-1=1-2cos^2(θ) ?

The answer to whether 2sin^2(θ)-1=1-2cos^2(θ) is True

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prove 2sin^2(θ)-1=1-2cos^2(θ)

prove

2 sin^{2} (θ) - 1 = 1 - 2 cos^{2} (θ)

True

Solution steps

2 sin^{2} (θ) - 1 = 1 - 2 cos^{2} (θ)

Manipulating left side

2 sin^{2} (θ) - 1

Rewrite using trig identities

= - 2 cos^{2} (θ) + 1

= 1 - 2 cos^{2} (θ)

We showed that the two sides could take the same form

\Rightarrow True

cos (θ - π) = - cos (θ)

\frac{tan ^{2} ( x )}{sin ^{2} ( x )} = tan^{2} (x) + 1

\frac{cot ^{2} ( θ )}{csc ^{2} ( θ )} = cos^{2} (θ)

(csc (a) + 1) (csc (a) - 1) = cot^{2} (a)

2 cos^{2} (A) - 1 = 1 - 2 sin^{2} (A)

Is 2sin^2(θ)-1=1-2cos^2(θ) ?
The answer to whether 2sin^2(θ)-1=1-2cos^2(θ) is True