Is csc(u)-sin(u)=cos(u)cot(u) ?

The answer to whether csc(u)-sin(u)=cos(u)cot(u) is True

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove csc(u)-sin(u)=cos(u)cot(u)

prove

csc (u) - sin (u) = cos (u) cot (u)

True

Solution steps

csc (u) - sin (u) = cos (u) cot (u)

Manipulating left side

csc (u) - sin (u)

Express with sin, cos

= \frac{1 - sin ^{2} ( u )}{sin ( u )}

Rewrite using trig identities

= \frac{cos ^{2} ( u )}{sin ( u )}

Rewrite using trig identities

cos (u) cot (u)

We showed that the two sides could take the same form

\Rightarrow True

\frac{tan ^{2} ( x )}{sec ( x ) - 1} = sec (x) + 1

\frac{1 + tan ^{2} ( x )}{csc ( x ) sec ( x )} = tan (x)

\frac{sin ( θ )}{csc ( θ ) - cot ( θ )} = 1 + cos (θ)

sec (θ) - tan (θ) sin (θ) = \frac{1}{sec ( θ )}

cot (- a) cos (- a) + sin (- a) = - csc (a)

Is csc(u)-sin(u)=cos(u)cot(u) ?
The answer to whether csc(u)-sin(u)=cos(u)cot(u) is True