Is (tan^2(x))/(sec(x)-1)=sec(x)+1 ?

The answer to whether (tan^2(x))/(sec(x)-1)=sec(x)+1 is True

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove (tan^2(x))/(sec(x)-1)=sec(x)+1

prove

\frac{tan ^{2} ( x )}{sec ( x ) - 1} = sec (x) + 1

True

Solution steps

\frac{tan ^{2} ( x )}{sec ( x ) - 1} = sec (x) + 1

Manipulating left side

\frac{tan ^{2} ( x )}{sec ( x ) - 1}

Rewrite using trig identities

= sec (x) + 1

We showed that the two sides could take the same form

\Rightarrow True

2 cos (x) tan (x) csc (x) = 2

sec^{2} (y) - cot^{2} (\frac{π}{2} - y) = 1

sin (\frac{π}{3} + x) - sin (\frac{π}{3} - x) = sin (x)

1 + cos (2 x) = 2 cos^{2} (x)

tan (x) (sin (x) + cot (x) cos (x)) = sec (x)

Is (tan^2(x))/(sec(x)-1)=sec(x)+1 ?
The answer to whether (tan^2(x))/(sec(x)-1)=sec(x)+1 is True