Is cos^2(θ/2)=(sec(θ)+1)/(2sec(θ)) ?

The answer to whether cos^2(θ/2)=(sec(θ)+1)/(2sec(θ)) is True

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prove cos^2(θ/2)=(sec(θ)+1)/(2sec(θ))

prove

cos^{2} (\frac{θ}{2}) = \frac{sec ( θ ) + 1}{2 sec ( θ )}

True

Solution steps

cos^{2} (\frac{θ}{2}) = \frac{sec ( θ ) + 1}{2 sec ( θ )}

Let:

u = \frac{θ}{2}

cos^{2} (u) = \frac{sec ( 2 u ) + 1}{2 sec ( 2 u )}

Prove

cos^{2} (u) = \frac{sec ( 2 u ) + 1}{2 sec ( 2 u )} :

True

Therefore

cos^{2} (\frac{θ}{2}) = \frac{sec ( θ ) + 1}{2 sec ( θ )}

We showed that the two sides could take the same form

\Rightarrow True

cos^{2} (x) = (cos (x))^{2}

2 cos^{2} (θ) tan (θ) = sin (2 θ)

sin^{5} (x) = (1 - cos^{2} (x))^{2} sin (x)

csc (x) sec (x) = cot (x) + tan (x)

cos (\frac{3 π}{2} - x) = - sin (x)

Is cos^2(θ/2)=(sec(θ)+1)/(2sec(θ)) ?
The answer to whether cos^2(θ/2)=(sec(θ)+1)/(2sec(θ)) is True