Is cot(u)tan(u)-sin^2(u)=cos^2(u) ?

The answer to whether cot(u)tan(u)-sin^2(u)=cos^2(u) is True

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prove cot(u)tan(u)-sin^2(u)=cos^2(u)

prove

cot (u) tan (u) - sin^{2} (u) = cos^{2} (u)

True

Solution steps

cot (u) tan (u) - sin^{2} (u) = cos^{2} (u)

Manipulating left side

cot (u) tan (u) - sin^{2} (u)

Express with sin, cos

= 1 - sin^{2} (u)

Rewrite using trig identities

= cos^{2} (u)

We showed that the two sides could take the same form

\Rightarrow True

\frac{1}{cos ( θ )} = \frac{tan ( θ )}{sin ( θ )}

(tan (y) + cot (y)) sin (y) cos (y) = 1

sin (x) \cdot cot (x) = cos (x)

(csc (θ) - cot (θ)) (csc (θ) + cot (θ)) = 1

1 + sin (x) cot (x) = 1 + cos (x)

Is cot(u)tan(u)-sin^2(u)=cos^2(u) ?
The answer to whether cot(u)tan(u)-sin^2(u)=cos^2(u) is True