Is (sec(θ))/(csc(θ))=tan(θ) ?

The answer to whether (sec(θ))/(csc(θ))=tan(θ) is True

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove (sec(θ))/(csc(θ))=tan(θ)

prove

\frac{sec ( θ )}{csc ( θ )} = tan (θ)

True

Solution steps

\frac{sec ( θ )}{csc ( θ )} = tan (θ)

Manipulating left side

\frac{sec ( θ )}{csc ( θ )}

Express with sin, cos

= \frac{sin ( θ )}{cos ( θ )}

Use the basic trigonometric identity:

\frac{sin ( x )}{cos ( x )} = tan (x)

= tan (θ)

We showed that the two sides could take the same form

\Rightarrow True

cos (2 x) + 1 = 2 cos^{2} (x)

tan (θ) \cdot cos (θ) = sin (θ)

csc (x) + cot (x) = \frac{1 + cos ( x )}{sin ( x )}

\frac{cos ( x )}{1 - sin ( x )} = tan (\frac{x}{2} - \frac{π}{4})

(sin (x))^{2} = sin^{2} (x)

Is (sec(θ))/(csc(θ))=tan(θ) ?
The answer to whether (sec(θ))/(csc(θ))=tan(θ) is True