Is cos^2(B)-sin^2(B)=1-2sin^2(B) ?

The answer to whether cos^2(B)-sin^2(B)=1-2sin^2(B) is True

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prove cos^2(B)-sin^2(B)=1-2sin^2(B)

prove

cos^{2} (B) - sin^{2} (B) = 1 - 2 sin^{2} (B)

True

Solution steps

cos^{2} (B) - sin^{2} (B) = 1 - 2 sin^{2} (B)

Manipulating left side

cos^{2} (B) - sin^{2} (B)

Rewrite using trig identities

= 1 - 2 sin^{2} (B)

We showed that the two sides could take the same form

\Rightarrow True

cot (u) tan (u) - cos^{2} (u) = sin^{2} (u)

\frac{csc ^{4} ( x ) - 1}{cot ^{2} ( x )} = csc^{2} (x) + 1

\frac{1}{csc ( x )} = sin (x)

sin (θ) + cos (θ) = 2 sin (θ + 4 5^{\circ})

\frac{1 - tan ( θ )}{1 + tan ( θ )} = \frac{cot ( θ ) - 1}{cot ( θ ) + 1}

Is cos^2(B)-sin^2(B)=1-2sin^2(B) ?
The answer to whether cos^2(B)-sin^2(B)=1-2sin^2(B) is True