Is sin(x)cos(x)+sin(3x)sec(x)=tan(x) ?

The answer to whether sin(x)cos(x)+sin(3x)sec(x)=tan(x) is False

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prove sin(x)cos(x)+sin(3x)sec(x)=tan(x)

prove

sin (x) cos (x) + sin (3 x) sec (x) = tan (x)

False

Solution steps

sin (x) cos (x) + sin (3 x) sec (x) = tan (x)

Show that the two sides are not equal

For

sin (x) cos (x) + sin (3 x) sec (x) = tan (x)

plug in

x = 1

sin (1) cos (1) + sin (3 \cdot 1) sec (1) = 0.71583 \dots

sin (1) cos (1) + sin (3 \cdot 1) sec (1)

Refine to a decimal form

= 0.71583 \dots

tan (1) = 1.55740 \dots

tan (1)

Refine to a decimal form

= 1.55740 \dots

The two sides are not equal

\Rightarrow False

tan (θ) + sec (θ) = \frac{cos ( θ )}{1 - sin ( θ )}

(1 + sec (x)) (1 - cos (x)) = sin (x) tan (x)

(sec (α)) (sec (α)) = tan (α)

cos^{2} (2 x) + sin^{2} (2 x) = 1

sec (x) \cdot sin (x) = tan (x)

Is sin(x)cos(x)+sin(3x)sec(x)=tan(x) ?
The answer to whether sin(x)cos(x)+sin(3x)sec(x)=tan(x) is False