Is 8cos^4(θ-8)sin^4(θ)=8cos(2θ) ?

The answer to whether 8cos^4(θ-8)sin^4(θ)=8cos(2θ) is False

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prove 8cos^4(θ-8)sin^4(θ)=8cos(2θ)

prove

8 cos^{4} (θ - 8) sin^{4} (θ) = 8 cos (2 θ)

False

Solution steps

8 cos^{4} (θ - 8) sin^{4} (θ) = 8 cos (2 θ)

Show that the two sides are not equal

\Rightarrow False

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\frac{1 - cos ( 2 θ ) + sin ( 2 θ )}{1 + cos ( 2 θ ) + sin ( 2 θ )} = tan (θ)

cot (x) sec^{2} (x) - cot (x) = tan (x)

\frac{cos ( θ )}{cos ( θ ) - 1} = \frac{1}{1 - sec ( θ )}

cos (- \frac{π}{4} - 5 t) = cos (5 t + \frac{π}{4})

Is 8cos^4(θ-8)sin^4(θ)=8cos(2θ) ?
The answer to whether 8cos^4(θ-8)sin^4(θ)=8cos(2θ) is False