Is tan^2(x)sec^2(x)-tan^2(x)=tan^4(x) ?

The answer to whether tan^2(x)sec^2(x)-tan^2(x)=tan^4(x) is True

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prove tan^2(x)sec^2(x)-tan^2(x)=tan^4(x)

prove

tan^{2} (x) sec^{2} (x) - tan^{2} (x) = tan^{4} (x)

True

Solution steps

tan^{2} (x) sec^{2} (x) - tan^{2} (x) = tan^{4} (x)

Manipulating left side

tan^{2} (x) sec^{2} (x) - tan^{2} (x)

Rewrite using trig identities

= tan^{4} (x)

We showed that the two sides could take the same form

\Rightarrow True

sin^{2} (x) + 3 cos^{2} (x) = 1 + 2 cos^{2} (x)

sec (2 θ) = \frac{csc ^{2} ( θ )}{csc ^{2} ( θ ) - 2}

sin (x + \frac{3 π}{2}) = - cos (x)

sec (x) - sec (x) \cdot sin^{2} (x) = cos (x)

\frac{2 sin ( x ) cos ( x )}{cos ( 2 x )} = tan (2 x)

Is tan^2(x)sec^2(x)-tan^2(x)=tan^4(x) ?
The answer to whether tan^2(x)sec^2(x)-tan^2(x)=tan^4(x) is True