Is 1+sec(x)=(cos(x)+1)/(cos(x)) ?

The answer to whether 1+sec(x)=(cos(x)+1)/(cos(x)) is True

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prove 1+sec(x)=(cos(x)+1)/(cos(x))

prove

1 + sec (x) = \frac{cos ( x ) + 1}{cos ( x )}

True

Solution steps

1 + sec (x) = \frac{cos ( x ) + 1}{cos ( x )}

Manipulating left side

1 + sec (x)

Express with sin, cos

= \frac{1 + cos ( x )}{cos ( x )}

= \frac{cos ( x ) + 1}{cos ( x )}

We showed that the two sides could take the same form

\Rightarrow True

tan (θ) + cot (θ) = csc (θ) sec (θ)

2 sin (x) + 1 = 3 csc (x)

sec (x) cot (x) = \frac{1}{sin ( x )}

sec (2 θ) = \frac{sec ^{2} ( θ ) csc ^{2} ( θ )}{csc ^{2} ( θ ) - sec ^{2} ( θ )}

sin^{2} (x) - 3 cos^{2} (x) = 1 - 4 cos^{2} (x)

Is 1+sec(x)=(cos(x)+1)/(cos(x)) ?
The answer to whether 1+sec(x)=(cos(x)+1)/(cos(x)) is True