What is the general solution for cos(β)=0.8 ?

The general solution for cos(β)=0.8 is β=0.64350…+2pin,β=2pi-0.64350…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(β)=0.8

cos (β) = 0.8

β = 0.64350 \dots + 2 πn, β = 2 π - 0.64350 \dots + 2 πn

Solution steps

cos (β) = 0.8

Apply trig inverse properties

β = arccos (0.8) + 2 πn, β = 2 π - arccos (0.8) + 2 πn

Show solutions in decimal form

β = 0.64350 \dots + 2 πn, β = 2 π - 0.64350 \dots + 2 πn

cos (15 0^{\circ})

2 sin^{2} (x) + cos (x) = 1

arcsin (\frac{3}{5})

arcsin (- \frac{3}{2})

cot (x) = \frac{sin ( 2 x )}{1 - cos ( 2 x )}

What is the general solution for cos(β)=0.8 ?
The general solution for cos(β)=0.8 is β=0.64350…+2pin,β=2pi-0.64350…+2pin