Is sec(b)+tan(b)=(cos(b))/(1-sin(b)) ?

The answer to whether sec(b)+tan(b)=(cos(b))/(1-sin(b)) is True

Popular >

prove sec(b)+tan(b)=(cos(b))/(1-sin(b))

prove

sec (b) + tan (b) = \frac{cos ( b )}{1 - sin ( b )}

True

Solution steps

sec (b) + tan (b) = \frac{cos ( b )}{1 - sin ( b )}

Manipulating left side

sec (b) + tan (b)

Express with sin, cos

= \frac{1 + sin ( b )}{cos ( b )}

Rewrite using trig identities

= \frac{cos ( b )}{1 - sin ( b )}

We showed that the two sides could take the same form

\Rightarrow True

cot^{4} (x) + cot^{2} (x) = csc^{4} (x) - csc^{2} (x)

tan (θ) + cot (θ) = \frac{1}{sin ( θ ) \cdot cos ( θ )}

cos (θ) cot (θ) = csc (θ) - sin (θ)

1 - tanh^{2} (x) = sech^{2} (x)

sin (x) (tan (x) + cot (x)) = sec (x)

Is sec(b)+tan(b)=(cos(b))/(1-sin(b)) ?
The answer to whether sec(b)+tan(b)=(cos(b))/(1-sin(b)) is True