Is cot(θ)csc(θ)tan^2(θ)=sec(θ) ?

The answer to whether cot(θ)csc(θ)tan^2(θ)=sec(θ) is True

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prove cot(θ)csc(θ)tan^2(θ)=sec(θ)

prove

cot (θ) csc (θ) tan^{2} (θ) = sec (θ)

True

Solution steps

cot (θ) csc (θ) tan^{2} (θ) = sec (θ)

Manipulating left side

cot (θ) csc (θ) tan^{2} (θ)

Express with sin, cos

= \frac{1}{cos ( θ )}

Rewrite using trig identities

sec (θ)

We showed that the two sides could take the same form

\Rightarrow True

\frac{cot ( x ) + cos ( x )}{1 + csc ( x )} = cos (x)

sin (z + \frac{π}{2}) = cos (z)

\frac{sec ( α )}{1 - cos ( α )} = \frac{sec ( α ) + 1}{sin ^{2} ( α )}

2 csc (2 x) = csc (x) sec (x)

cos (\frac{π}{4}) = \frac{2}{2}

Is cot(θ)csc(θ)tan^2(θ)=sec(θ) ?
The answer to whether cot(θ)csc(θ)tan^2(θ)=sec(θ) is True