Is 80=arcsin(45.6443*(sin(c))/(35)) ?

The answer to whether 80=arcsin(45.6443*(sin(c))/(35)) is False

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prove 80=arcsin(45.6443*(sin(c))/(35))

prove

80 = arcsin (45.6443 \cdot \frac{sin ( c )}{35})

False

Solution steps

80 = arcsin (45.6443 \cdot \frac{sin ( c )}{35})

Show that the two sides are not equal

\Rightarrow False

\frac{( tan ^{2} ( x ) )}{sec ( x )} = sin (x) tan (x)

cos (x) (1 + tan (x))^{2} = sec (x) + 2 sin (x)

cos (x) cot (x) = \frac{1}{sin ( x )} - sin (x)

tan (θ) = \frac{sec ( θ )}{csc ( θ )}

\frac{sec ( θ )}{csc ^{2} ( θ )} = sec (θ) - cos (θ)

Is 80=arcsin(45.6443*(sin(c))/(35)) ?
The answer to whether 80=arcsin(45.6443*(sin(c))/(35)) is False