Is (cos(θ)+1)/(sin(θ))=cot(θ)+csc(θ) ?

The answer to whether (cos(θ)+1)/(sin(θ))=cot(θ)+csc(θ) is True

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prove (cos(θ)+1)/(sin(θ))=cot(θ)+csc(θ)

prove

\frac{cos ( θ ) + 1}{sin ( θ )} = cot (θ) + csc (θ)

True

Solution steps

\frac{cos ( θ ) + 1}{sin ( θ )} = cot (θ) + csc (θ)

Manipulating right side

cot (θ) + csc (θ)

Express with sin, cos

= \frac{1 + cos ( θ )}{sin ( θ )}

= \frac{cos ( θ ) + 1}{sin ( θ )}

We showed that the two sides could take the same form

\Rightarrow True

cos (2 A) = 2 cos^{2} (A) - 1

2 sin^{2} (3 x) = 1 - cos (6 x)

sec^{2} (x) - 1 = \frac{tan ( x )}{cot ( x )}

sec (θ) cos (θ) = 1

cot (θ) (cot (θ) + tan (θ)) = csc^{2} (θ)

Is (cos(θ)+1)/(sin(θ))=cot(θ)+csc(θ) ?
The answer to whether (cos(θ)+1)/(sin(θ))=cot(θ)+csc(θ) is True