Is prove-tan^2(x)+sec^2(x)=1 ?

The answer to whether prove-tan^2(x)+sec^2(x)=1 is True

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prove-tan^2(x)+sec^2(x)=1

prove

- tan^{2} (x) + sec^{2} (x) = 1

True

Solution steps

- tan^{2} (x) + sec^{2} (x) = 1

Use the Pythagorean identity:

sec^{2} (x) = tan^{2} (x) + 1

sec^{2} (x) - tan^{2} (x) = 1

\Rightarrow True

tan (2 θ) = \frac{2 cot ( θ )}{cot ^{2} ( θ ) - 1}

cos (3 x) - cos (x) = 4 cos^{3} (x) - 4 cos (x)

cot^{2} (θ) - cos^{2} (θ) = cos^{2} (θ) cot^{2} (θ)

\frac{tan ( A )}{sec ( A )} = sin (A)

tan (8 x) - tan (8 x) tan^{2} (4 x) = 2 tan (4 x)

Is prove-tan^2(x)+sec^2(x)=1 ?
The answer to whether prove-tan^2(x)+sec^2(x)=1 is True