Is (sin(θ)csc(θ))/(cot(θ))=tan(θ) ?

The answer to whether (sin(θ)csc(θ))/(cot(θ))=tan(θ) is True

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prove (sin(θ)csc(θ))/(cot(θ))=tan(θ)

prove

\frac{sin ( θ ) csc ( θ )}{cot ( θ )} = tan (θ)

True

Solution steps

\frac{sin ( θ ) csc ( θ )}{cot ( θ )} = tan (θ)

Manipulating left side

\frac{sin ( θ ) csc ( θ )}{cot ( θ )}

Express with sin, cos

= \frac{sin ( θ )}{cos ( θ )}

Use the basic trigonometric identity:

\frac{sin ( x )}{cos ( x )} = tan (x)

= tan (θ)

We showed that the two sides could take the same form

\Rightarrow True

\frac{sin ( 2 x )}{2} = sin (x) cos (x)

sin (θ) = sin^{3} (θ) + cos^{2} (θ) sin (θ)

\frac{csc ( θ ) - cot ( θ )}{sec ( θ ) - 1} = cot (θ)

sin^{2} (z) + cos^{2} (z) = 1

tan (x) sin (x) = cos (x)

Is (sin(θ)csc(θ))/(cot(θ))=tan(θ) ?
The answer to whether (sin(θ)csc(θ))/(cot(θ))=tan(θ) is True