Is cos^2(θ)tan^2(θ)=sin^2(θ) ?

The answer to whether cos^2(θ)tan^2(θ)=sin^2(θ) is True

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prove cos^2(θ)tan^2(θ)=sin^2(θ)

prove

cos^{2} (θ) tan^{2} (θ) = sin^{2} (θ)

True

Solution steps

cos^{2} (θ) tan^{2} (θ) = sin^{2} (θ)

Manipulating left side

cos^{2} (θ) tan^{2} (θ)

Express with sin, cos

= sin^{2} (θ)

We showed that the two sides could take the same form

\Rightarrow True

1 - cot (x) = csc^{2} (x) - 2 cot (x)

sin^{2} (x) + cot^{2} (x) sin^{2} (x) = 1

\frac{1 - cos ^{2} ( θ )}{tan ^{2} ( θ )} = cos^{2} (θ)

tan^{2} (θ) cos^{2} (θ) = sin^{2} (θ)

\frac{csc ^{2} ( x )}{cot ^{2} ( x )} = 1 + tan^{2} (x)

Is cos^2(θ)tan^2(θ)=sin^2(θ) ?
The answer to whether cos^2(θ)tan^2(θ)=sin^2(θ) is True