Is (tan(θ))/(sin(θ))=sec(θ) ?

The answer to whether (tan(θ))/(sin(θ))=sec(θ) is True

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prove (tan(θ))/(sin(θ))=sec(θ)

prove

\frac{tan ( θ )}{sin ( θ )} = sec (θ)

True

Solution steps

\frac{tan ( θ )}{sin ( θ )} = sec (θ)

Manipulating left side

\frac{tan ( θ )}{sin ( θ )}

Express with sin, cos

= \frac{1}{cos ( θ )}

Rewrite using trig identities

sec (θ)

We showed that the two sides could take the same form

\Rightarrow True

tan (u) - sec (u) = \frac{cos ( u )}{1 + sin ( u )}

cot^{2} (x) + 1 = \frac{1}{sin ^{2} ( x )}

cos (2 θ) = cos^{4} (θ) - sin^{4} (θ)

\frac{sin ( 2 A )}{1 - cos ( 2 A )} = cot (A)

sin (6 x) = 2 sin (3 x) cos (3 x)

Is (tan(θ))/(sin(θ))=sec(θ) ?
The answer to whether (tan(θ))/(sin(θ))=sec(θ) is True