Is sec^2(θ)cot^2(θ)=csc^2(θ) ?

The answer to whether sec^2(θ)cot^2(θ)=csc^2(θ) is True

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prove sec^2(θ)cot^2(θ)=csc^2(θ)

prove

sec^{2} (θ) cot^{2} (θ) = csc^{2} (θ)

True

Solution steps

sec^{2} (θ) cot^{2} (θ) = csc^{2} (θ)

Manipulating left side

sec^{2} (θ) cot^{2} (θ)

Express with sin, cos

= \frac{1}{sin ^{2} ( θ )}

Rewrite using trig identities

csc^{2} (θ)

We showed that the two sides could take the same form

\Rightarrow True

tan (\frac{3 π}{2} - x) = cot (x)

\frac{3 csc ( - x )}{sec ( - x )} = - 3 cot (x)

\frac{1 - tan ^{4} ( x )}{1 - tan ^{2} ( x )} = sec^{2} (x)

\frac{sin ( x )}{1 + cos ( x )} = tan (\frac{x}{2})

cos (4 x) = 1 - 2 sin^{2} (2 x)

Is sec^2(θ)cot^2(θ)=csc^2(θ) ?
The answer to whether sec^2(θ)cot^2(θ)=csc^2(θ) is True