Is cos(pi-x)+sin(pi/2+x)=0 ?

The answer to whether cos(pi-x)+sin(pi/2+x)=0 is True

Popular >

prove cos(pi-x)+sin(pi/2+x)=0

prove

cos (π - x) + sin (\frac{π}{2} + x) = 0

True

Solution steps

cos (π - x) + sin (\frac{π}{2} + x) = 0

Manipulating left side

cos (π - x) + sin (\frac{π}{2} + x)

Rewrite using trig identities

= - cos (x) + sin (\frac{π}{2} + x)

Rewrite using trig identities

= - cos (x) + cos (x)

Add similar elements:

- cos (x) + cos (x) = 0

= 0

We showed that the two sides could take the same form

\Rightarrow True

cot^{2} (x) csc^{2} (x) - cot^{2} (x) = cot^{4} (x)

arcsin (x) = csc (x)

\frac{1}{tan ( x ) csc ( x ) sin ( x )} = cot (x)

(1 - sin (x)) (1 + csc (x)) = cos (x) cot (x)

\frac{1}{cos ( x )} = \frac{tan ( x )}{sin ( x )}

Is cos(pi-x)+sin(pi/2+x)=0 ?
The answer to whether cos(pi-x)+sin(pi/2+x)=0 is True