Is cos(θ)sec(θ)-cos^2(θ)=sin^2(θ) ?

The answer to whether cos(θ)sec(θ)-cos^2(θ)=sin^2(θ) is True

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prove cos(θ)sec(θ)-cos^2(θ)=sin^2(θ)

prove

cos (θ) sec (θ) - cos^{2} (θ) = sin^{2} (θ)

True

Solution steps

cos (θ) sec (θ) - cos^{2} (θ) = sin^{2} (θ)

Manipulating left side

cos (θ) sec (θ) - cos^{2} (θ)

Express with sin, cos

= 1 - cos^{2} (θ)

Rewrite using trig identities

= sin^{2} (θ)

We showed that the two sides could take the same form

\Rightarrow True

sin (12 x) = 2 sin (6 x) cos (6 x)

\frac{sin ( t )}{csc ( t )} = 1 - \frac{cos ( t )}{sec ( t )}

cot^{2} (x) = 1 - csc^{2} (x)

tan^{4} (θ) = tan^{2} (θ) sec^{2} (θ) - tan^{2} (θ)

1 + cos (θ) = \frac{sin ^{2} ( θ )}{1 - cos ( θ )}

Is cos(θ)sec(θ)-cos^2(θ)=sin^2(θ) ?
The answer to whether cos(θ)sec(θ)-cos^2(θ)=sin^2(θ) is True