Is sin^2(θ)sec(θ)csc(θ)=tan(θ) ?

The answer to whether sin^2(θ)sec(θ)csc(θ)=tan(θ) is True

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prove sin^2(θ)sec(θ)csc(θ)=tan(θ)

prove

sin^{2} (θ) sec (θ) csc (θ) = tan (θ)

True

Solution steps

sin^{2} (θ) sec (θ) csc (θ) = tan (θ)

Manipulating left side

sin^{2} (θ) sec (θ) csc (θ)

Express with sin, cos

= \frac{sin ( θ )}{cos ( θ )}

Use the basic trigonometric identity:

\frac{sin ( x )}{cos ( x )} = tan (x)

= tan (θ)

We showed that the two sides could take the same form

\Rightarrow True

csc (x) (cos (x) + sin (x)) = cot (x) + 1

cos^{2} (x) + cos^{2} (x) cot^{2} (x) = cot^{2} (x)

\frac{1 - cos ^{4} ( x )}{sin ^{2} ( x )} = 1 + cos^{2} (x)

2 cot^{2} (A) sin^{2} (A) = 1 + cos (2 A)

sin (x) + cos (x) = cos (x) (1 + tan (x))

Is sin^2(θ)sec(θ)csc(θ)=tan(θ) ?
The answer to whether sin^2(θ)sec(θ)csc(θ)=tan(θ) is True