Is 1=sec^2(x)-tan^2(x) ?

The answer to whether 1=sec^2(x)-tan^2(x) is True

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prove 1=sec^2(x)-tan^2(x)

prove

1 = sec^{2} (x) - tan^{2} (x)

True

Solution steps

1 = sec^{2} (x) - tan^{2} (x)

Use the Pythagorean identity:

tan^{2} (x) + 1 = sec^{2} (x)

1 = sec^{2} (x) - tan^{2} (x)

\Rightarrow True

\frac{sec ^{2} ( x ) - 6 tan ( x ) + 7}{sec ^{2} ( x ) - 5} = \frac{tan ( x ) - 4}{tan ( x ) + 2}

1 - cos (x) = 2 sin^{2} (\frac{x}{2})

cos (3 A) = 4 cos^{3} (A) - 3 cos (A)

sin (a) cot (a) = cos (a)

cos (3 θ) = cos^{3} (θ) - 3 sin^{2} (θ) cos (θ)