Is 1+sin(θ)=(cos^2(θ))/(1-sin(θ)) ?

The answer to whether 1+sin(θ)=(cos^2(θ))/(1-sin(θ)) is True

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prove 1+sin(θ)=(cos^2(θ))/(1-sin(θ))

prove

1 + sin (θ) = \frac{cos ^{2} ( θ )}{1 - sin ( θ )}

True

Solution steps

1 + sin (θ) = \frac{cos ^{2} ( θ )}{1 - sin ( θ )}

Manipulating right side

\frac{cos ^{2} ( θ )}{1 - sin ( θ )}

Rewrite using trig identities

= sin (θ) + 1

= 1 + sin (θ)

We showed that the two sides could take the same form

\Rightarrow True

\frac{2 sin ^{2} ( t )}{tan ^{2} ( t )} = 2 cos^{2} (t)

tan (2 θ) = \frac{2 tan ( θ )}{( 1 - tan ( 2 θ ) )}

tan (A) \cdot cot (A) = 1

\frac{1}{csc ( y ) - cot ( y )} = csc (y) + cot (y)

\frac{tan ^{2} ( x )}{sec ^{2} ( x )} = sin^{2} (x)

Is 1+sin(θ)=(cos^2(θ))/(1-sin(θ)) ?
The answer to whether 1+sin(θ)=(cos^2(θ))/(1-sin(θ)) is True