Is (1-cos(2θ))/2 =sin^2(θ) ?

The answer to whether (1-cos(2θ))/2 =sin^2(θ) is True

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prove (1-cos(2θ))/2 =sin^2(θ)

prove

\frac{1 - cos ( 2 θ )}{2} = sin^{2} (θ)

True

Solution steps

\frac{1 - cos ( 2 θ )}{2} = sin^{2} (θ)

Manipulating left side

\frac{1 - cos ( 2 θ )}{2}

Rewrite using trig identities

= sin^{2} (θ)

We showed that the two sides could take the same form

\Rightarrow True

(sec (θ) + tan (θ)) (1 - sin (θ)) = cos (θ)

\frac{csc ^{4} ( x ) - 1}{cot ^{2} ( x )} = 2 + cot^{2} (x)

sin (arcsin (x) + arccos (x)) = 1

\frac{1}{2 csc ( 2 x )} = cos^{2} (x) tan (x)

(sec (5 x) - 1) (sec (5 x) - 1) = tan^{2} (5 x)

Is (1-cos(2θ))/2 =sin^2(θ) ?
The answer to whether (1-cos(2θ))/2 =sin^2(θ) is True