Is cot^2(x)sin^2(x)=cos^2(x) ?

The answer to whether cot^2(x)sin^2(x)=cos^2(x) is True

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prove cot^2(x)sin^2(x)=cos^2(x)

prove

cot^{2} (x) sin^{2} (x) = cos^{2} (x)

True

Solution steps

cot^{2} (x) sin^{2} (x) = cos^{2} (x)

Manipulating left side

cot^{2} (x) sin^{2} (x)

Express with sin, cos

= cos^{2} (x)

We showed that the two sides could take the same form

\Rightarrow True

\frac{cos ( θ )}{tan ( θ ) + sec ( θ )} = 1 - sin (θ)

sec (x) - tan (x) (sin (x)) = \frac{1}{sec ( x )}

sin^{2} (x) + 2 cos^{2} (x) - 1 = cos^{2} (x)

\frac{1 - tan ^{4} ( x )}{sec ^{2} ( x )} = 1 - tan^{2} (x)

tan^{2} (x) = sec (x) csc (x) tan (x) - 1

Is cot^2(x)sin^2(x)=cos^2(x) ?
The answer to whether cot^2(x)sin^2(x)=cos^2(x) is True