Is sec(θ)=cos(θ)+cos(θ)tan^2(θ) ?

The answer to whether sec(θ)=cos(θ)+cos(θ)tan^2(θ) is True

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prove sec(θ)=cos(θ)+cos(θ)tan^2(θ)

prove

sec (θ) = cos (θ) + cos (θ) tan^{2} (θ)

True

Solution steps

sec (θ) = cos (θ) + cos (θ) tan^{2} (θ)

Manipulating right side

cos (θ) + cos (θ) tan^{2} (θ)

Express with sin, cos

= \frac{cos ^{2} ( θ ) + sin ^{2} ( θ )}{cos ( θ )}

Rewrite using trig identities

= \frac{1}{cos ( θ )}

Rewrite using trig identities

sec (θ)

We showed that the two sides could take the same form

\Rightarrow True

\frac{cot ( x ) + csc ( x ) cos ( x )}{cot ( x )} = 2

sec (θ) - cos (θ) = sin (θ) \cdot tan (θ)

(2 sin (x) + cos (x))^{2} + (2 cos (x) - sin (x))^{2} = 5

cos (a) (sec (a) - cos (a)) = sin^{2} (a)

tan (x) cos (x) csc (x) = 1

Is sec(θ)=cos(θ)+cos(θ)tan^2(θ) ?
The answer to whether sec(θ)=cos(θ)+cos(θ)tan^2(θ) is True