Is cos(a-b)-cos(a+b)=2sin(a)sin(b) ?

The answer to whether cos(a-b)-cos(a+b)=2sin(a)sin(b) is True

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prove cos(a-b)-cos(a+b)=2sin(a)sin(b)

prove

cos (a - b) - cos (a + b) = 2 sin (a) sin (b)

True

Solution steps

cos (a - b) - cos (a + b) = 2 sin (a) sin (b)

Manipulating right side

2 sin (a) sin (b)

Rewrite using trig identities

= cos (a - b) - cos (a + b)

We showed that the two sides could take the same form

\Rightarrow True

tan (θ) sin (θ) = sec (θ) - cos (θ)

\frac{sec ( θ )}{tan ( θ )} = csc (θ)

cot (2 b) = \frac{cot ^{2} ( b ) - 1}{2 cot ( b )}

1 + tan^{2} (a) = sec^{2} (a)

2 cos (x) cos (y) = cos (x + y) + cos (x - y)

Is cos(a-b)-cos(a+b)=2sin(a)sin(b) ?
The answer to whether cos(a-b)-cos(a+b)=2sin(a)sin(b) is True