Is tan(θ)cot(θ)-1=1-sec(θ)cos(θ) ?

The answer to whether tan(θ)cot(θ)-1=1-sec(θ)cos(θ) is True

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prove tan(θ)cot(θ)-1=1-sec(θ)cos(θ)

prove

tan (θ) cot (θ) - 1 = 1 - sec (θ) cos (θ)

True

Solution steps

tan (θ) cot (θ) - 1 = 1 - sec (θ) cos (θ)

Manipulating left side

tan (θ) cot (θ) - 1

Express with sin, cos

= 0

Manipulating right side

1 - sec (θ) cos (θ)

Express with sin, cos

= 0

We showed that the two sides could take the same form

\Rightarrow True

\frac{cot ( 2 x )}{cos ( 2 x )} = csc (2 x)

(tan (θ) + 1) (tan (θ) - 1) = sec^{2} (θ) - 2

\frac{sec ( t ) - 1}{1 - cos ( t )} = sec (t)

tan (\frac{7 π}{6}) = \frac{3}{3}

\frac{1 - cos ^{2} ( x )}{tan ( x )} = sin (x) cos (x)

Is tan(θ)cot(θ)-1=1-sec(θ)cos(θ) ?
The answer to whether tan(θ)cot(θ)-1=1-sec(θ)cos(θ) is True