Is 10sec^2(θ)-4tan^2(θ)=4+6sec^2(θ) ?

The answer to whether 10sec^2(θ)-4tan^2(θ)=4+6sec^2(θ) is True

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prove 10sec^2(θ)-4tan^2(θ)=4+6sec^2(θ)

prove

10 sec^{2} (θ) - 4 tan^{2} (θ) = 4 + 6 sec^{2} (θ)

True

Solution steps

10 sec^{2} (θ) - 4 tan^{2} (θ) = 4 + 6 sec^{2} (θ)

Manipulating left side

10 sec^{2} (θ) - 4 tan^{2} (θ)

Rewrite using trig identities

= 6 sec^{2} (θ) + 4

= 4 + 6 sec^{2} (θ)

We showed that the two sides could take the same form

\Rightarrow True

tan (x) = \frac{( 1 - cos ( 2 x ) )}{sin ( 2 x )}

sin^{2} (a) - cos^{2} (a) = 1 - 2 cos^{2} (a)

tan (2 A) - 2 tan (2 A) sin^{2} (A) = sin (2 A)

\frac{1}{tan ( x ) csc ( x )} = cos (x)

tan (4 θ) + tan (2 θ) = sec (4 θ) - sec (2 θ)

Is 10sec^2(θ)-4tan^2(θ)=4+6sec^2(θ) ?
The answer to whether 10sec^2(θ)-4tan^2(θ)=4+6sec^2(θ) is True