Is tan^2(x)+sec^2(x)=cot^2(x) ?

The answer to whether tan^2(x)+sec^2(x)=cot^2(x) is False

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prove tan^2(x)+sec^2(x)=cot^2(x)

prove

tan^{2} (x) + sec^{2} (x) = cot^{2} (x)

False

Solution steps

tan^{2} (x) + sec^{2} (x) = cot^{2} (x)

Show that the two sides are not equal

\Rightarrow False

csc (x) - 1 = \frac{1 - sin ( x )}{sin ( x )}

tan (x) sin (x) = \frac{sec ^{2} ( x ) - 1}{sec ( x )}

cos (θ - 6 0^{\circ}) + cos (θ + 6 0^{\circ}) = cos (θ)

tan (2 A) = \frac{2 tan ( A )}{1 - tan ^{2} ( A )}

sin (x) - csc (x) = \frac{- cos ^{2} ( x )}{sin ( x )}

Is tan^2(x)+sec^2(x)=cot^2(x) ?
The answer to whether tan^2(x)+sec^2(x)=cot^2(x) is False