Is 6cos^2(x)-3=3-6sin^2(x) ?

The answer to whether 6cos^2(x)-3=3-6sin^2(x) is True

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prove 6cos^2(x)-3=3-6sin^2(x)

prove

6 cos^{2} (x) - 3 = 3 - 6 sin^{2} (x)

True

Solution steps

6 cos^{2} (x) - 3 = 3 - 6 sin^{2} (x)

Manipulating left side

6 cos^{2} (x) - 3

Rewrite using trig identities

= - 6 sin^{2} (x) + 3

= 3 - 6 sin^{2} (x)

We showed that the two sides could take the same form

\Rightarrow True

sin (x) tan (x) + cos (- x) = sec (x)

2 sin^{2} (4 5^{\circ}) = 1 - cos (9 0^{\circ})

(1 - cos (B)) (1 + cos (B)) = \frac{1}{csc ^{2} ( B )}

cot (θ) - tan (θ) = 2 cot (2 θ)

sin^{2} (u) = \frac{1 - cos ( 2 u )}{2}

Is 6cos^2(x)-3=3-6sin^2(x) ?
The answer to whether 6cos^2(x)-3=3-6sin^2(x) is True