Is (sin(θ))/(csc(θ))=sin^2(θ) ?

The answer to whether (sin(θ))/(csc(θ))=sin^2(θ) is True

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prove (sin(θ))/(csc(θ))=sin^2(θ)

prove

\frac{sin ( θ )}{csc ( θ )} = sin^{2} (θ)

True

Solution steps

\frac{sin ( θ )}{csc ( θ )} = sin^{2} (θ)

Manipulating left side

\frac{sin ( θ )}{csc ( θ )}

Express with sin, cos

= sin^{2} (θ)

We showed that the two sides could take the same form

\Rightarrow True

tan (\frac{2 π}{3}) = - 3

tan (π - x) = tan (x)

1 + sin (2 x) = 2 cos (x - 4 5^{\circ})

sin^{2} (x) cos^{2} (x) = \frac{1}{4} sin^{2} (2 x)

cos^{3} (θ) + sin^{2} (θ) cos (θ) = cos (θ)

Is (sin(θ))/(csc(θ))=sin^2(θ) ?
The answer to whether (sin(θ))/(csc(θ))=sin^2(θ) is True